Addition, subtraction, and multiplication of complex numbers extend the rules for real numbers. Division is done a bit differently but still follow rules you already know for real numbers.

Addition: To add two complex numbers, just add the real parts and the imaginary parts separately. Example:

(2 – 5*i*) + (-3 +2*i*) = (2 – 3) + (-5 + 2)*i* = -1 – 3*i*

Subtraction: same as addition, you just separately subtract the real parts and the imaginary parts. Example:

(2 – 5*i*) – (-3 +2*i*) = (2 – (-3)) + (-5 – (+2))*i* = 5 – 7*i*

Multiplication: Just as for real algebraic expressions like (*x* + *y*)(2*x* + 3*y*), you just multiply two complex numbers the same way then add like terms. Just remember that *i*² = -1 so a negative sign will appear when *i* is multiplied by *i*. Example:

(2 – 5*i*) × (-3 +2*i*) = 2 × (-3) + 2 × 2*i* -5*i* × (-3) – 5*i* × 2*i*

= -6 + 4*i* + 15*i* -10*i*² = -6 + 19*i* -10(-1) = 4 + 19*i*

The same method applies when multiplying a real number times a complex number:

2 × (2 – 5*i*) = 4 – 10*i*

Before I talk about division, I need to introduce another definition. In my last post, I solved a quadratic equation with the solution -2 ± 3*i*. So there are two solutions, one with the + and the other with the -. These two solutions are called a *complex conjugate pair*. -2 + 3*i* is the complex conjugate of -2 – 3*i* and vice versa. It turns out that if a polynomial equation has a complex solution, the conjugate of that solution is also a solution. That is, complex solutions to polynomial equations always come in complex conjugate pairs. If *z* is a complex number, *z*̄ is used to represent its conjugate.

So now let’s look at complex division. To divide by a complex number (which include real numbers) by a complex number with a non-zero imaginary part, multiply the numerator and denominator by the conjugate of the denominator. Example:

\[(2-5i)\div (-3+2i)=\frac{2-5i}{-3+2i}\times \frac{-3-2i}{-3-2i}=\frac{-6-4i+15i-10}{9+6i-6i+4}\] \[=\frac{-16+11i}{13}=-\frac{16}{13}+\frac{11}{13}i\]This example illustrates a few more things about complex numbers. First, at the end, dividing a complex number by a pure real number (or multiplying for that matter), you just divide (or multiply) each part of the complex number by the real number.

The other thing you may have noticed is in the multiplication in the denominator. Multiplying a complex number by its conjugate results in a real number. This resulting number has graphical significance which you will see later. In general, if *z* = *x* + *yi*, then *z*̄ = *x* – *yi* and z *z*̄ = *x*² + *y*².

In my last post, I found that -2 ± 3*i* are solutions to *z*² +4*z* + 13 = 0. Let’s check one of these solutions:

(-2 + 3*i*)² + 4(-2 + 3*i*) +13 = 4 -12*i* -9 – 8 + 12*i* + 13 = 0 + 0*i*

I’ll leave it to you to show that the conjugate also solves the equation.

Note that two complex numbers are equal only if their real parts are equal and their imaginary parts are equal.

In my next post, I’ll look at how we can plot complex numbers.